Base | Representation |
---|---|
bin | 1011000110111001101110… |
… | …1000100101011010101111 |
3 | 1121020120102010101021202211 |
4 | 2301232123220211122233 |
5 | 3100100120000130111 |
6 | 41550400145031251 |
7 | 2400242362506001 |
oct | 261563350453257 |
9 | 47216363337684 |
10 | 12213203130031 |
11 | 3989654851012 |
12 | 1453001025527 |
13 | 6a79141c2627 |
14 | 30319d3c4371 |
15 | 162a6056d521 |
hex | b1b9ba256af |
12213203130031 has 2 divisors, whose sum is σ = 12213203130032. Its totient is φ = 12213203130030.
The previous prime is 12213203130019. The next prime is 12213203130049. The reversal of 12213203130031 is 13003130231221.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12213203130031 is a prime.
It is a super-2 number, since 2×122132031300312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12213203129984 and 12213203130011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12213203130001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106601565015 + 6106601565016.
It is an arithmetic number, because the mean of its divisors is an integer number (6106601565016).
Almost surely, 212213203130031 is an apocalyptic number.
12213203130031 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213203130031 is an equidigital number, since it uses as much as digits as its factorization.
12213203130031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 12213203130031 its reverse (13003130231221), we get a palindrome (25216333361252).
The spelling of 12213203130031 in words is "twelve trillion, two hundred thirteen billion, two hundred three million, one hundred thirty thousand, thirty-one".
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