Base | Representation |
---|---|
bin | 1011000110111010001000… |
… | …0000010011001101011111 |
3 | 1121020120200120111100210212 |
4 | 2301232202000103031133 |
5 | 3100100324330311312 |
6 | 41550414523523035 |
7 | 2400245131125005 |
oct | 261564200231537 |
9 | 47216616440725 |
10 | 12213310010207 |
11 | 39896aa111739 |
12 | 145303098947b |
13 | 6a79303a4937 |
14 | 3031ad686a75 |
15 | 162a69b31822 |
hex | b1ba201335f |
12213310010207 has 2 divisors, whose sum is σ = 12213310010208. Its totient is φ = 12213310010206.
The previous prime is 12213310010191. The next prime is 12213310010221. The reversal of 12213310010207 is 70201001331221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12213310010207 - 24 = 12213310010191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12213310010227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106655005103 + 6106655005104.
It is an arithmetic number, because the mean of its divisors is an integer number (6106655005104).
Almost surely, 212213310010207 is an apocalyptic number.
12213310010207 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213310010207 is an equidigital number, since it uses as much as digits as its factorization.
12213310010207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 12213310010207 its reverse (70201001331221), we get a palindrome (82414311341428).
The spelling of 12213310010207 in words is "twelve trillion, two hundred thirteen billion, three hundred ten million, ten thousand, two hundred seven".
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