Base | Representation |
---|---|
bin | 1011000110111010101010… |
… | …1011000010011000001111 |
3 | 1121020121001201010111212221 |
4 | 2301232222223002120033 |
5 | 3100101124042244213 |
6 | 41550441200440211 |
7 | 2400251545153606 |
oct | 261565253023017 |
9 | 47217051114787 |
10 | 12213455431183 |
11 | 3989774206666 |
12 | 1453071619067 |
13 | 6a795455c556 |
14 | 3031c4adca3d |
15 | 162a777a938d |
hex | b1baaac260f |
12213455431183 has 2 divisors, whose sum is σ = 12213455431184. Its totient is φ = 12213455431182.
The previous prime is 12213455431159. The next prime is 12213455431223. The reversal of 12213455431183 is 38113455431221.
12213455431183 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12213455431183 - 213 = 12213455422991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12213455431783) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106727715591 + 6106727715592.
It is an arithmetic number, because the mean of its divisors is an integer number (6106727715592).
Almost surely, 212213455431183 is an apocalyptic number.
12213455431183 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213455431183 is an equidigital number, since it uses as much as digits as its factorization.
12213455431183 is an evil number, because the sum of its binary digits is even.
The product of its digits is 345600, while the sum is 43.
The spelling of 12213455431183 in words is "twelve trillion, two hundred thirteen billion, four hundred fifty-five million, four hundred thirty-one thousand, one hundred eighty-three".
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