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1221443300131 is a prime number
BaseRepresentation
bin10001110001100011101…
…100011010101100100011
311022202202111001121210121
4101301203230122230203
5130003003441101011
62333042344541111
7154150334514025
oct21614354325443
94282674047717
101221443300131
1143101399993a
12178882a81797
138b248cc1a92
1443192394015
1521b8c500e71
hex11c63b1ab23

1221443300131 has 2 divisors, whose sum is σ = 1221443300132. Its totient is φ = 1221443300130.

The previous prime is 1221443300111. The next prime is 1221443300153. The reversal of 1221443300131 is 1310033441221.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1221443300131 - 217 = 1221443169059 is a prime.

It is a super-2 number, since 2×12214433001312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1221443300096 and 1221443300105.

It is not a weakly prime, because it can be changed into another prime (1221443300111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610721650065 + 610721650066.

It is an arithmetic number, because the mean of its divisors is an integer number (610721650066).

Almost surely, 21221443300131 is an apocalyptic number.

1221443300131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1221443300131 is an equidigital number, since it uses as much as digits as its factorization.

1221443300131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1221443300131 its reverse (1310033441221), we get a palindrome (2531476741352).

The spelling of 1221443300131 in words is "one trillion, two hundred twenty-one billion, four hundred forty-three million, three hundred thousand, one hundred thirty-one".