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12215003535463 is a prime number
BaseRepresentation
bin1011000111000000011011…
…1100100101100001100111
31121020202001121011100201111
42301300012330211201213
53100112311401113323
641551254542005451
72400335113632301
oct261600674454147
947222047140644
1012215003535463
11398a399062293
121453423b76887
136a7b401c50a1
143032d0564971
15162b18656c0d
hexb1c06f25867

12215003535463 has 2 divisors, whose sum is σ = 12215003535464. Its totient is φ = 12215003535462.

The previous prime is 12215003535437. The next prime is 12215003535467. The reversal of 12215003535463 is 36453530051221.

It is a strong prime.

It is an emirp because it is prime and its reverse (36453530051221) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12215003535463 is a prime.

It is a super-2 number, since 2×122150035354632 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12215003535467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6107501767731 + 6107501767732.

It is an arithmetic number, because the mean of its divisors is an integer number (6107501767732).

Almost surely, 212215003535463 is an apocalyptic number.

12215003535463 is a deficient number, since it is larger than the sum of its proper divisors (1).

12215003535463 is an equidigital number, since it uses as much as digits as its factorization.

12215003535463 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324000, while the sum is 40.

Adding to 12215003535463 its reverse (36453530051221), we get a palindrome (48668533586684).

The spelling of 12215003535463 in words is "twelve trillion, two hundred fifteen billion, three million, five hundred thirty-five thousand, four hundred sixty-three".