Base | Representation |
---|---|
bin | 10110110000001010… |
… | …00111111010111101 |
3 | 1011112021222020110111 |
4 | 23120011013322331 |
5 | 200004040001123 |
6 | 5340033110021 |
7 | 611463054625 |
oct | 133005077275 |
9 | 34467866414 |
10 | 12215156413 |
11 | 51a9156899 |
12 | 244a9b8311 |
13 | 11c88c7705 |
14 | 83c427885 |
15 | 4b75c090d |
hex | 2d8147ebd |
12215156413 has 2 divisors, whose sum is σ = 12215156414. Its totient is φ = 12215156412.
The previous prime is 12215156351. The next prime is 12215156419. The reversal of 12215156413 is 31465151221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8397523044 + 3817633369 = 91638^2 + 61787^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12215156413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12215156419) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6107578206 + 6107578207.
It is an arithmetic number, because the mean of its divisors is an integer number (6107578207).
Almost surely, 212215156413 is an apocalyptic number.
It is an amenable number.
12215156413 is a deficient number, since it is larger than the sum of its proper divisors (1).
12215156413 is an equidigital number, since it uses as much as digits as its factorization.
12215156413 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7200, while the sum is 31.
The spelling of 12215156413 in words is "twelve billion, two hundred fifteen million, one hundred fifty-six thousand, four hundred thirteen".
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