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12220000201111 is a prime number
BaseRepresentation
bin1011000111010011000011…
…0001010110100110010111
31121021012221211021021102011
42301310300301112212113
53100203030022413421
641553442433525051
72400602665611523
oct261646061264627
947235854237364
1012220000201111
1139915225a212a
121454399413787
136a8458457091
14303645dd8d83
15162d0c1504e1
hexb1d30c56997

12220000201111 has 2 divisors, whose sum is σ = 12220000201112. Its totient is φ = 12220000201110.

The previous prime is 12220000201103. The next prime is 12220000201151. The reversal of 12220000201111 is 11110200002221.

12220000201111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12220000201111 - 23 = 12220000201103 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12220000201091 and 12220000201100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12220000201151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110000100555 + 6110000100556.

It is an arithmetic number, because the mean of its divisors is an integer number (6110000100556).

Almost surely, 212220000201111 is an apocalyptic number.

12220000201111 is a deficient number, since it is larger than the sum of its proper divisors (1).

12220000201111 is an equidigital number, since it uses as much as digits as its factorization.

12220000201111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 12220000201111 its reverse (11110200002221), we get a palindrome (23330200203332).

The spelling of 12220000201111 in words is "twelve trillion, two hundred twenty billion, two hundred one thousand, one hundred eleven".