Base | Representation |
---|---|
bin | 1011000111010011001001… |
… | …0110010001001100111011 |
3 | 1121021020000200001022002002 |
4 | 2301310302112101030323 |
5 | 3100203103310434142 |
6 | 41553445220531215 |
7 | 2400603436512254 |
oct | 261646226211473 |
9 | 47236020038062 |
10 | 12220026655547 |
11 | 39915365207a7 |
12 | 14543a6250b0b |
13 | 6a8460a8a2a9 |
14 | 303649723b2b |
15 | 162d0e628a32 |
hex | b1d3259133b |
12220026655547 has 2 divisors, whose sum is σ = 12220026655548. Its totient is φ = 12220026655546.
The previous prime is 12220026655519. The next prime is 12220026655553. The reversal of 12220026655547 is 74555662002221.
12220026655547 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12220026655547 - 234 = 12202846786363 is a prime.
It is not a weakly prime, because it can be changed into another prime (12220026655847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110013327773 + 6110013327774.
It is an arithmetic number, because the mean of its divisors is an integer number (6110013327774).
Almost surely, 212220026655547 is an apocalyptic number.
12220026655547 is a deficient number, since it is larger than the sum of its proper divisors (1).
12220026655547 is an equidigital number, since it uses as much as digits as its factorization.
12220026655547 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016000, while the sum is 47.
Adding to 12220026655547 its reverse (74555662002221), we get a palindrome (86775688657768).
The spelling of 12220026655547 in words is "twelve trillion, two hundred twenty billion, twenty-six million, six hundred fifty-five thousand, five hundred forty-seven".
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