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12220032320141 is a prime number
BaseRepresentation
bin1011000111010011001010…
…1011111000001010001101
31121021020001001201002102212
42301310302223320022031
53100203111233221031
641553445542200205
72400603535614152
oct261646253701215
947236031632385
1012220032320141
11399153973a688
1214543a8123065
136a8461cc1719
1430364a39a229
15162d0ed9712b
hexb1d32af828d

12220032320141 has 2 divisors, whose sum is σ = 12220032320142. Its totient is φ = 12220032320140.

The previous prime is 12220032320129. The next prime is 12220032320147. The reversal of 12220032320141 is 14102323002221.

12220032320141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10988920022116 + 1231112298025 = 3314954^2 + 1109555^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12220032320141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12220032320147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110016160070 + 6110016160071.

It is an arithmetic number, because the mean of its divisors is an integer number (6110016160071).

Almost surely, 212220032320141 is an apocalyptic number.

It is an amenable number.

12220032320141 is a deficient number, since it is larger than the sum of its proper divisors (1).

12220032320141 is an equidigital number, since it uses as much as digits as its factorization.

12220032320141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12220032320141 its reverse (14102323002221), we get a palindrome (26322355322362).

The spelling of 12220032320141 in words is "twelve trillion, two hundred twenty billion, thirty-two million, three hundred twenty thousand, one hundred forty-one".