Base | Representation |
---|---|
bin | 11011110010010011010110… |
… | …110011110001010000001111 |
3 | 121000200120220210211110201020 |
4 | 123302103112303301100033 |
5 | 112004142304412313403 |
6 | 1111523425421045223 |
7 | 34511643242036124 |
oct | 3362232663612017 |
9 | 530616823743636 |
10 | 122204013401103 |
11 | 35a35481792907 |
12 | 11857b589b6813 |
13 | 5325a3461455a |
14 | 22269c4a4274b |
15 | e1dc180c8453 |
hex | 6f24d6cf140f |
122204013401103 has 64 divisors (see below), whose sum is σ = 170867850734592. Its totient is φ = 77540997980160.
The previous prime is 122204013401087. The next prime is 122204013401153. The reversal of 122204013401103 is 301104310402221.
It is not a de Polignac number, because 122204013401103 - 24 = 122204013401087 is a prime.
It is a super-2 number, since 2×1222040134011032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (122204013401153) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 44005765051 + ... + 44005767827.
It is an arithmetic number, because the mean of its divisors is an integer number (2669810167728).
Almost surely, 2122204013401103 is an apocalyptic number.
122204013401103 is a deficient number, since it is larger than the sum of its proper divisors (48663837333489).
122204013401103 is a wasteful number, since it uses less digits than its factorization.
122204013401103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5984.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 122204013401103 its reverse (301104310402221), we get a palindrome (423308323803324).
The spelling of 122204013401103 in words is "one hundred twenty-two trillion, two hundred four billion, thirteen million, four hundred one thousand, one hundred three".
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