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1222102112113 is a prime number
BaseRepresentation
bin10001110010001010111…
…101100101011101110001
311022211110101201201221101
4101302022331211131301
5130010331120041423
62333232001324401
7154202554361461
oct21621275453561
94284411651841
101222102112113
11431321867053
12178a27636701
138b32263c95c
1443215a89ba1
1521bca2897ad
hex11c8af65771

1222102112113 has 2 divisors, whose sum is σ = 1222102112114. Its totient is φ = 1222102112112.

The previous prime is 1222102112009. The next prime is 1222102112141. The reversal of 1222102112113 is 3112112012221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 809402510224 + 412699601889 = 899668^2 + 642417^2 .

It is an emirp because it is prime and its reverse (3112112012221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1222102112113 - 213 = 1222102103921 is a prime.

It is not a weakly prime, because it can be changed into another prime (1222102110113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611051056056 + 611051056057.

It is an arithmetic number, because the mean of its divisors is an integer number (611051056057).

Almost surely, 21222102112113 is an apocalyptic number.

It is an amenable number.

1222102112113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1222102112113 is an equidigital number, since it uses as much as digits as its factorization.

1222102112113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 1222102112113 its reverse (3112112012221), we get a palindrome (4334214124334).

The spelling of 1222102112113 in words is "one trillion, two hundred twenty-two billion, one hundred two million, one hundred twelve thousand, one hundred thirteen".