Base | Representation |
---|---|
bin | 1011000111010111001010… |
… | …0001011000110001101111 |
3 | 1121021022210200222010001101 |
4 | 2301311302201120301233 |
5 | 3100212304421440413 |
6 | 41554144121223531 |
7 | 2400642222112306 |
oct | 261656241306157 |
9 | 47238720863041 |
10 | 12221103311983 |
11 | 3991a39241705 |
12 | 1454646931ba7 |
13 | 6a85a2b569c7 |
14 | 30370c70743d |
15 | 162d73decedd |
hex | b1d72858c6f |
12221103311983 has 2 divisors, whose sum is σ = 12221103311984. Its totient is φ = 12221103311982.
The previous prime is 12221103311927. The next prime is 12221103312037. The reversal of 12221103311983 is 38911330112221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12221103311983 - 213 = 12221103303791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12221106311983) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110551655991 + 6110551655992.
It is an arithmetic number, because the mean of its divisors is an integer number (6110551655992).
Almost surely, 212221103311983 is an apocalyptic number.
12221103311983 is a deficient number, since it is larger than the sum of its proper divisors (1).
12221103311983 is an equidigital number, since it uses as much as digits as its factorization.
12221103311983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 37.
The spelling of 12221103311983 in words is "twelve trillion, two hundred twenty-one billion, one hundred three million, three hundred eleven thousand, nine hundred eighty-three".
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