Base | Representation |
---|---|
bin | 1011000111010111001100… |
… | …0010111010010010001011 |
3 | 1121021022211022111120220201 |
4 | 2301311303002322102023 |
5 | 3100212314144144404 |
6 | 41554145033433031 |
7 | 2400642356603266 |
oct | 261656302722213 |
9 | 47238738446821 |
10 | 12221112099979 |
11 | 3991a431a4212 |
12 | 145464986b777 |
13 | 6a85a49129c3 |
14 | 30370d953cdd |
15 | 162d74a86ca4 |
hex | b1d730ba48b |
12221112099979 has 2 divisors, whose sum is σ = 12221112099980. Its totient is φ = 12221112099978.
The previous prime is 12221112099961. The next prime is 12221112099983. The reversal of 12221112099979 is 97999021112221.
12221112099979 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (97999021112221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12221112099979 - 215 = 12221112067211 is a prime.
It is a super-4 number, since 4×122211120999794 (a number of 53 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (12221112099929) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110556049989 + 6110556049990.
It is an arithmetic number, because the mean of its divisors is an integer number (6110556049990).
Almost surely, 212221112099979 is an apocalyptic number.
12221112099979 is a deficient number, since it is larger than the sum of its proper divisors (1).
12221112099979 is an equidigital number, since it uses as much as digits as its factorization.
12221112099979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 734832, while the sum is 55.
The spelling of 12221112099979 in words is "twelve trillion, two hundred twenty-one billion, one hundred twelve million, ninety-nine thousand, nine hundred seventy-nine".
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