Base | Representation |
---|---|
bin | 1011000111010111001100… |
… | …0010111010010010001111 |
3 | 1121021022211022111120220212 |
4 | 2301311303002322102033 |
5 | 3100212314144144413 |
6 | 41554145033433035 |
7 | 2400642356603303 |
oct | 261656302722217 |
9 | 47238738446825 |
10 | 12221112099983 |
11 | 3991a431a4216 |
12 | 145464986b77b |
13 | 6a85a49129c7 |
14 | 30370d953d03 |
15 | 162d74a86ca8 |
hex | b1d730ba48f |
12221112099983 has 2 divisors, whose sum is σ = 12221112099984. Its totient is φ = 12221112099982.
The previous prime is 12221112099979. The next prime is 12221112100049. The reversal of 12221112099983 is 38999021112221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12221112099983 - 22 = 12221112099979 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12221112099923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110556049991 + 6110556049992.
It is an arithmetic number, because the mean of its divisors is an integer number (6110556049992).
Almost surely, 212221112099983 is an apocalyptic number.
12221112099983 is a deficient number, since it is larger than the sum of its proper divisors (1).
12221112099983 is an equidigital number, since it uses as much as digits as its factorization.
12221112099983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 279936, while the sum is 50.
The spelling of 12221112099983 in words is "twelve trillion, two hundred twenty-one billion, one hundred twelve million, ninety-nine thousand, nine hundred eighty-three".
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