Base | Representation |
---|---|
bin | 10110110000110111… |
… | …11100110100110001 |
3 | 1011112201020020202221 |
4 | 23120123330310301 |
5 | 200012102442043 |
6 | 5340405241041 |
7 | 611564656366 |
oct | 133033746461 |
9 | 34481206687 |
10 | 12221140273 |
11 | 5201573631 |
12 | 2450a03181 |
13 | 11c9c11264 |
14 | 83d14446d |
15 | 4b7da38ed |
hex | 2d86fcd31 |
12221140273 has 2 divisors, whose sum is σ = 12221140274. Its totient is φ = 12221140272.
The previous prime is 12221140201. The next prime is 12221140301. The reversal of 12221140273 is 37204112221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10094823729 + 2126316544 = 100473^2 + 46112^2 .
It is a cyclic number.
It is not a de Polignac number, because 12221140273 - 229 = 11684269361 is a prime.
It is not a weakly prime, because it can be changed into another prime (12221140073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110570136 + 6110570137.
It is an arithmetic number, because the mean of its divisors is an integer number (6110570137).
Almost surely, 212221140273 is an apocalyptic number.
It is an amenable number.
12221140273 is a deficient number, since it is larger than the sum of its proper divisors (1).
12221140273 is an equidigital number, since it uses as much as digits as its factorization.
12221140273 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 12221140273 its reverse (37204112221), we get a palindrome (49425252494).
The spelling of 12221140273 in words is "twelve billion, two hundred twenty-one million, one hundred forty thousand, two hundred seventy-three".
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