Base | Representation |
---|---|
bin | 10001110010001100001… |
… | …001011111100111101001 |
3 | 11022211111210011201020101 |
4 | 101302030021133213221 |
5 | 130010401213323423 |
6 | 2333233552025401 |
7 | 154203215460163 |
oct | 21621411374751 |
9 | 4284453151211 |
10 | 1222122011113 |
11 | 431332018503 |
12 | 178a32232261 |
13 | 8b3267b9103 |
14 | 43218589933 |
15 | 21bcbdba7ad |
hex | 11c8c25f9e9 |
1222122011113 has 2 divisors, whose sum is σ = 1222122011114. Its totient is φ = 1222122011112.
The previous prime is 1222122011081. The next prime is 1222122011119. The reversal of 1222122011113 is 3111102212221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1168630185024 + 53491826089 = 1081032^2 + 231283^2 .
It is an emirp because it is prime and its reverse (3111102212221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1222122011113 - 25 = 1222122011081 is a prime.
It is not a weakly prime, because it can be changed into another prime (1222122011119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611061005556 + 611061005557.
It is an arithmetic number, because the mean of its divisors is an integer number (611061005557).
Almost surely, 21222122011113 is an apocalyptic number.
It is an amenable number.
1222122011113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1222122011113 is an equidigital number, since it uses as much as digits as its factorization.
1222122011113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 1222122011113 its reverse (3111102212221), we get a palindrome (4333224223334).
The spelling of 1222122011113 in words is "one trillion, two hundred twenty-two billion, one hundred twenty-two million, eleven thousand, one hundred thirteen".
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