Search a number
-
+
1222133000117 is a prime number
BaseRepresentation
bin10001110010001100110…
…011011010011110110101
311022211112112212000022112
4101302030303122132311
5130010412022000432
62333235023340405
7154203411046121
oct21621463323665
94284475760275
101222133000117
11431338243727
12178a35a51705
138b328b65b93
1443219c0a581
1521bccd3b7b2
hex11c8ccda7b5

1222133000117 has 2 divisors, whose sum is σ = 1222133000118. Its totient is φ = 1222133000116.

The previous prime is 1222133000071. The next prime is 1222133000159. The reversal of 1222133000117 is 7110003312221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 659139391876 + 562993608241 = 811874^2 + 750329^2 .

It is a cyclic number.

It is not a de Polignac number, because 1222133000117 - 214 = 1222132983733 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1222133000092 and 1222133000101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1222133020117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611066500058 + 611066500059.

It is an arithmetic number, because the mean of its divisors is an integer number (611066500059).

Almost surely, 21222133000117 is an apocalyptic number.

It is an amenable number.

1222133000117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1222133000117 is an equidigital number, since it uses as much as digits as its factorization.

1222133000117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 1222133000117 its reverse (7110003312221), we get a palindrome (8332136312338).

The spelling of 1222133000117 in words is "one trillion, two hundred twenty-two billion, one hundred thirty-three million, one hundred seventeen", and thus it is an aban number.