Base | Representation |
---|---|
bin | 1011000111011000000101… |
… | …1001000100001101110011 |
3 | 1121021100110002101211222101 |
4 | 2301312001121010031303 |
5 | 3100213312303220401 |
6 | 41554224552321231 |
7 | 2400651341455153 |
oct | 261660131041563 |
9 | 47240402354871 |
10 | 12221352788851 |
11 | 3992057048338 |
12 | 14546b63a3217 |
13 | 6a861274525b |
14 | 3037338c8763 |
15 | 162d8ac7c101 |
hex | b1d81644373 |
12221352788851 has 2 divisors, whose sum is σ = 12221352788852. Its totient is φ = 12221352788850.
The previous prime is 12221352788783. The next prime is 12221352788861. The reversal of 12221352788851 is 15888725312221.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12221352788851 is a prime.
It is a super-2 number, since 2×122213527888512 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12221352788792 and 12221352788801.
It is not a weakly prime, because it can be changed into another prime (12221352788861) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110676394425 + 6110676394426.
It is an arithmetic number, because the mean of its divisors is an integer number (6110676394426).
Almost surely, 212221352788851 is an apocalyptic number.
12221352788851 is a deficient number, since it is larger than the sum of its proper divisors (1).
12221352788851 is an equidigital number, since it uses as much as digits as its factorization.
12221352788851 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4300800, while the sum is 55.
The spelling of 12221352788851 in words is "twelve trillion, two hundred twenty-one billion, three hundred fifty-two million, seven hundred eighty-eight thousand, eight hundred fifty-one".
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