Base | Representation |
---|---|
bin | 10001110010001101001… |
… | …111011010101111010011 |
3 | 11022211120001122222101121 |
4 | 101302031033122233103 |
5 | 130010420411404303 |
6 | 2333235444543111 |
7 | 154203530332525 |
oct | 21621517325723 |
9 | 4284501588347 |
10 | 1222140341203 |
11 | 4313413a8141 |
12 | 178a383b1a97 |
13 | 8b32a536412 |
14 | 4321ab9ba15 |
15 | 21bcd7db9bd |
hex | 11c8d3dabd3 |
1222140341203 has 2 divisors, whose sum is σ = 1222140341204. Its totient is φ = 1222140341202.
The previous prime is 1222140341153. The next prime is 1222140341231. The reversal of 1222140341203 is 3021430412221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1222140341203 - 221 = 1222138244051 is a prime.
It is not a weakly prime, because it can be changed into another prime (1222140341293) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611070170601 + 611070170602.
It is an arithmetic number, because the mean of its divisors is an integer number (611070170602).
Almost surely, 21222140341203 is an apocalyptic number.
1222140341203 is a deficient number, since it is larger than the sum of its proper divisors (1).
1222140341203 is an equidigital number, since it uses as much as digits as its factorization.
1222140341203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1222140341203 its reverse (3021430412221), we get a palindrome (4243570753424).
The spelling of 1222140341203 in words is "one trillion, two hundred twenty-two billion, one hundred forty million, three hundred forty-one thousand, two hundred three".
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