Base | Representation |
---|---|
bin | 10001110010001101011… |
… | …010110010010000100001 |
3 | 11022211120021021101001221 |
4 | 101302031122302100201 |
5 | 130010422142233441 |
6 | 2333240032455041 |
7 | 154203564553402 |
oct | 21621532622041 |
9 | 4284507241057 |
10 | 1222143321121 |
11 | 431343052a88 |
12 | 178a393aa481 |
13 | 8b32b03a898 |
14 | 4321b3359a9 |
15 | 21bcdbc98d1 |
hex | 11c8d6b2421 |
1222143321121 has 2 divisors, whose sum is σ = 1222143321122. Its totient is φ = 1222143321120.
The previous prime is 1222143321107. The next prime is 1222143321169. The reversal of 1222143321121 is 1211233412221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1197790158096 + 24353163025 = 1094436^2 + 156055^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1222143321121 is a prime.
It is not a weakly prime, because it can be changed into another prime (1222143321221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611071660560 + 611071660561.
It is an arithmetic number, because the mean of its divisors is an integer number (611071660561).
Almost surely, 21222143321121 is an apocalyptic number.
It is an amenable number.
1222143321121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1222143321121 is an equidigital number, since it uses as much as digits as its factorization.
1222143321121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1152, while the sum is 25.
Adding to 1222143321121 its reverse (1211233412221), we get a palindrome (2433376733342).
The spelling of 1222143321121 in words is "one trillion, two hundred twenty-two billion, one hundred forty-three million, three hundred twenty-one thousand, one hundred twenty-one".
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