Base | Representation |
---|---|
bin | 1011000111011010100100… |
… | …1110001000001000111111 |
3 | 1121021102011122210000001012 |
4 | 2301312221032020020333 |
5 | 3100221144334304413 |
6 | 41554415142505435 |
7 | 2401004034321551 |
oct | 261665116101077 |
9 | 47242148700035 |
10 | 12222021009983 |
11 | 399236a261804 |
12 | 145486213527b |
13 | 6a86bb008a85 |
14 | 30379854d4d1 |
15 | 162dc97737a8 |
hex | b1da938823f |
12222021009983 has 2 divisors, whose sum is σ = 12222021009984. Its totient is φ = 12222021009982.
The previous prime is 12222021009953. The next prime is 12222021010009. The reversal of 12222021009983 is 38990012022221.
12222021009983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12222021009983 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12222021009983.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12222021009953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6111010504991 + 6111010504992.
It is an arithmetic number, because the mean of its divisors is an integer number (6111010504992).
Almost surely, 212222021009983 is an apocalyptic number.
12222021009983 is a deficient number, since it is larger than the sum of its proper divisors (1).
12222021009983 is an equidigital number, since it uses as much as digits as its factorization.
12222021009983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 41.
The spelling of 12222021009983 in words is "twelve trillion, two hundred twenty-two billion, twenty-one million, nine thousand, nine hundred eighty-three".
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