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122223132021223 is a prime number
BaseRepresentation
bin11011110010100101001010…
…010111100001000111100111
3121000202102021012220000001201
4123302211022113201013213
5112010000433244134343
61111540310503303331
734513221102445312
oct3362451227410747
9530672235800051
10122223132021223
1135a425a2748102
121185b7b374ab47
135327790514b1c
1422278b9c57979
15e1e48679494d
hex6f294a5e11e7

122223132021223 has 2 divisors, whose sum is σ = 122223132021224. Its totient is φ = 122223132021222.

The previous prime is 122223132021157. The next prime is 122223132021229. The reversal of 122223132021223 is 322120231322221.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 122223132021223 - 229 = 122222595150311 is a prime.

It is a super-2 number, since 2×1222231320212232 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 122223132021191 and 122223132021200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122223132021229) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61111566010611 + 61111566010612.

It is an arithmetic number, because the mean of its divisors is an integer number (61111566010612).

Almost surely, 2122223132021223 is an apocalyptic number.

122223132021223 is a deficient number, since it is larger than the sum of its proper divisors (1).

122223132021223 is an equidigital number, since it uses as much as digits as its factorization.

122223132021223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 122223132021223 its reverse (322120231322221), we get a palindrome (444343363343444).

The spelling of 122223132021223 in words is "one hundred twenty-two trillion, two hundred twenty-three billion, one hundred thirty-two million, twenty-one thousand, two hundred twenty-three".