Base | Representation |
---|---|
bin | 1011000111011111000101… |
… | …0110101011011010010111 |
3 | 1121021112021222222120221222 |
4 | 2301313301112223122113 |
5 | 3100231134142224114 |
6 | 41555135213400555 |
7 | 2401046031005063 |
oct | 261676126533227 |
9 | 47245258876858 |
10 | 12223231211159 |
11 | 39929303a5871 |
12 | 1454b3b49915b |
13 | 6a8851962547 |
14 | 303871176aa3 |
15 | 162e4ab2698e |
hex | b1df15ab697 |
12223231211159 has 2 divisors, whose sum is σ = 12223231211160. Its totient is φ = 12223231211158.
The previous prime is 12223231211129. The next prime is 12223231211173. The reversal of 12223231211159 is 95111213232221.
It is a strong prime.
It is an emirp because it is prime and its reverse (95111213232221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12223231211159 - 216 = 12223231145623 is a prime.
It is a super-2 number, since 2×122232312111592 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12223231211129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6111615605579 + 6111615605580.
It is an arithmetic number, because the mean of its divisors is an integer number (6111615605580).
Almost surely, 212223231211159 is an apocalyptic number.
12223231211159 is a deficient number, since it is larger than the sum of its proper divisors (1).
12223231211159 is an equidigital number, since it uses as much as digits as its factorization.
12223231211159 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12960, while the sum is 35.
The spelling of 12223231211159 in words is "twelve trillion, two hundred twenty-three billion, two hundred thirty-one million, two hundred eleven thousand, one hundred fifty-nine".
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