Base | Representation |
---|---|
bin | 11011110010101101101110… |
… | …100111100001001001010011 |
3 | 121000210022000020202100020021 |
4 | 123302231232213201021103 |
5 | 112010123303003130003 |
6 | 1111544431322524311 |
7 | 34513665042206062 |
oct | 3362555647411123 |
9 | 530708006670207 |
10 | 122232330130003 |
11 | 35a4649284a3a5 |
12 | 11861540066697 |
13 | 53285c8039642 |
14 | 222810d6bc1d9 |
15 | e1e8240552bd |
hex | 6f2b6e9e1253 |
122232330130003 has 2 divisors, whose sum is σ = 122232330130004. Its totient is φ = 122232330130002.
The previous prime is 122232330129937. The next prime is 122232330130019. The reversal of 122232330130003 is 300031033232221.
It is a strong prime.
It is an emirp because it is prime and its reverse (300031033232221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122232330130003 - 221 = 122232328032851 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 122232330130003.
It is not a weakly prime, because it can be changed into another prime (122232330130063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61116165065001 + 61116165065002.
It is an arithmetic number, because the mean of its divisors is an integer number (61116165065002).
Almost surely, 2122232330130003 is an apocalyptic number.
122232330130003 is a deficient number, since it is larger than the sum of its proper divisors (1).
122232330130003 is an equidigital number, since it uses as much as digits as its factorization.
122232330130003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 122232330130003 its reverse (300031033232221), we get a palindrome (422263363362224).
The spelling of 122232330130003 in words is "one hundred twenty-two trillion, two hundred thirty-two billion, three hundred thirty million, one hundred thirty thousand, three".
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