Base | Representation |
---|---|
bin | 10001110010011001010… |
… | …101000010010001010001 |
3 | 11022212002012021020122012 |
4 | 101302121111002101101 |
5 | 130011324320443213 |
6 | 2333311531352305 |
7 | 154211542156112 |
oct | 21623125022121 |
9 | 4285065236565 |
10 | 1222343140433 |
11 | 431435922208 |
12 | 178a942b2695 |
13 | 8b36056086c |
14 | 43239aac209 |
15 | 21be14ea4a8 |
hex | 11c99542451 |
1222343140433 has 2 divisors, whose sum is σ = 1222343140434. Its totient is φ = 1222343140432.
The previous prime is 1222343140411. The next prime is 1222343140451. The reversal of 1222343140433 is 3340413432221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1153009931089 + 69333209344 = 1073783^2 + 263312^2 .
It is a cyclic number.
It is not a de Polignac number, because 1222343140433 - 220 = 1222342091857 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1222343140433.
It is not a weakly prime, because it can be changed into another prime (1222343140483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611171570216 + 611171570217.
It is an arithmetic number, because the mean of its divisors is an integer number (611171570217).
Almost surely, 21222343140433 is an apocalyptic number.
It is an amenable number.
1222343140433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1222343140433 is an equidigital number, since it uses as much as digits as its factorization.
1222343140433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 1222343140433 its reverse (3340413432221), we get a palindrome (4562756572654).
The spelling of 1222343140433 in words is "one trillion, two hundred twenty-two billion, three hundred forty-three million, one hundred forty thousand, four hundred thirty-three".
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