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12223433129 is a prime number
BaseRepresentation
bin10110110001001001…
…01100100110101001
31011112212112201222112
423120210230212221
5200013144330004
65340530332105
7611623316165
oct133044544651
934485481875
1012223433129
11520289a256
12245172a035
1311ca534a8b
1483d57dca5
154b81a7e6e
hex2d892c9a9

12223433129 has 2 divisors, whose sum is σ = 12223433130. Its totient is φ = 12223433128.

The previous prime is 12223433087. The next prime is 12223433149. The reversal of 12223433129 is 92133432221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10125793129 + 2097640000 = 100627^2 + 45800^2 .

It is a cyclic number.

It is not a de Polignac number, because 12223433129 - 220 = 12222384553 is a prime.

It is a super-3 number, since 3×122234331293 (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12223433095 and 12223433104.

It is not a weakly prime, because it can be changed into another prime (12223433149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6111716564 + 6111716565.

It is an arithmetic number, because the mean of its divisors is an integer number (6111716565).

Almost surely, 212223433129 is an apocalyptic number.

It is an amenable number.

12223433129 is a deficient number, since it is larger than the sum of its proper divisors (1).

12223433129 is an equidigital number, since it uses as much as digits as its factorization.

12223433129 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15552, while the sum is 32.

The spelling of 12223433129 in words is "twelve billion, two hundred twenty-three million, four hundred thirty-three thousand, one hundred twenty-nine".