Base | Representation |
---|---|
bin | 10001110011000000011… |
… | …110110000011001101111 |
3 | 11022220202222021011201102 |
4 | 101303000132300121233 |
5 | 130014201000000421 |
6 | 2333501034233315 |
7 | 154234036322651 |
oct | 21630036603157 |
9 | 4286688234642 |
10 | 1223000000111 |
11 | 43174268664a |
12 | 17903828583b |
13 | 8b436676c26 |
14 | 4329d0166d1 |
15 | 21c2deea60b |
hex | 11cc07b066f |
1223000000111 has 2 divisors, whose sum is σ = 1223000000112. Its totient is φ = 1223000000110.
The previous prime is 1223000000063. The next prime is 1223000000119. The reversal of 1223000000111 is 1110000003221.
It is a strong prime.
It is an emirp because it is prime and its reverse (1110000003221) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1223000000111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1223000000092 and 1223000000101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1223000000119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611500000055 + 611500000056.
It is an arithmetic number, because the mean of its divisors is an integer number (611500000056).
Almost surely, 21223000000111 is an apocalyptic number.
1223000000111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1223000000111 is an equidigital number, since it uses as much as digits as its factorization.
1223000000111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 1223000000111 its reverse (1110000003221), we get a palindrome (2333000003332).
The spelling of 1223000000111 in words is "one trillion, two hundred twenty-three billion, one hundred eleven", and thus it is an aban number.
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