Base | Representation |
---|---|
bin | 1011000111111000010011… |
… | …0100110000001111010101 |
3 | 1121022011202202020121102201 |
4 | 2301332010310300033111 |
5 | 3100334020040011201 |
6 | 42002215023004501 |
7 | 2401405544301541 |
oct | 261760464601725 |
9 | 47264682217381 |
10 | 12230000313301 |
11 | 3995794383461 |
12 | 145630a439731 |
13 | 6a9390183624 |
14 | 303d1418aa21 |
15 | 1631e5031801 |
hex | b1f84d303d5 |
12230000313301 has 2 divisors, whose sum is σ = 12230000313302. Its totient is φ = 12230000313300.
The previous prime is 12230000313287. The next prime is 12230000313319. The reversal of 12230000313301 is 10331300003221.
12230000313301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10055558102500 + 2174442210801 = 3171050^2 + 1474599^2 .
It is a cyclic number.
It is not a de Polignac number, because 12230000313301 - 217 = 12230000182229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12230000313701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6115000156650 + 6115000156651.
It is an arithmetic number, because the mean of its divisors is an integer number (6115000156651).
Almost surely, 212230000313301 is an apocalyptic number.
It is an amenable number.
12230000313301 is a deficient number, since it is larger than the sum of its proper divisors (1).
12230000313301 is an equidigital number, since it uses as much as digits as its factorization.
12230000313301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 12230000313301 its reverse (10331300003221), we get a palindrome (22561300316522).
The spelling of 12230000313301 in words is "twelve trillion, two hundred thirty billion, three hundred thirteen thousand, three hundred one".
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