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12230120334209 is a prime number
BaseRepresentation
bin1011000111111000101111…
…1110100110001110000001
31121022012002010002022011112
42301332023332212032001
53100334241301143314
642002234551253105
72401411532410661
oct261761376461601
947265063068145
1012230120334209
1139958460a9998
12145634267a195
136a93abcb6c0b
14303d260b01a1
1516320083d43e
hexb1f8bfa6381

12230120334209 has 2 divisors, whose sum is σ = 12230120334210. Its totient is φ = 12230120334208.

The previous prime is 12230120334199. The next prime is 12230120334217. The reversal of 12230120334209 is 90243302103221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11280865690000 + 949254644209 = 3358700^2 + 974297^2 .

It is an emirp because it is prime and its reverse (90243302103221) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12230120334209 is a prime.

It is a super-3 number, since 3×122301203342093 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (12230120334259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6115060167104 + 6115060167105.

It is an arithmetic number, because the mean of its divisors is an integer number (6115060167105).

Almost surely, 212230120334209 is an apocalyptic number.

It is an amenable number.

12230120334209 is a deficient number, since it is larger than the sum of its proper divisors (1).

12230120334209 is an equidigital number, since it uses as much as digits as its factorization.

12230120334209 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 32.

The spelling of 12230120334209 in words is "twelve trillion, two hundred thirty billion, one hundred twenty million, three hundred thirty-four thousand, two hundred nine".