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12230140032401 is a prime number
BaseRepresentation
bin1011000111111000110100…
…1001101111010110010001
31121022012010111011002000012
42301332031021233112101
53100334311322014101
642002240533404305
72401412162012054
oct261761511572621
947265114132005
1012230140032401
113995856233495
121456349199695
136a93b30c2b55
14303d2895aa9b
1516320242ebbb
hexb1f8d26f591

12230140032401 has 2 divisors, whose sum is σ = 12230140032402. Its totient is φ = 12230140032400.

The previous prime is 12230140032349. The next prime is 12230140032403. The reversal of 12230140032401 is 10423004103221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8486011781776 + 3744128250625 = 2913076^2 + 1934975^2 .

It is an emirp because it is prime and its reverse (10423004103221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12230140032401 - 210 = 12230140031377 is a prime.

Together with 12230140032403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12230140032403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6115070016200 + 6115070016201.

It is an arithmetic number, because the mean of its divisors is an integer number (6115070016201).

Almost surely, 212230140032401 is an apocalyptic number.

It is an amenable number.

12230140032401 is a deficient number, since it is larger than the sum of its proper divisors (1).

12230140032401 is an equidigital number, since it uses as much as digits as its factorization.

12230140032401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12230140032401 its reverse (10423004103221), we get a palindrome (22653144135622).

The spelling of 12230140032401 in words is "twelve trillion, two hundred thirty billion, one hundred forty million, thirty-two thousand, four hundred one".