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122310013131253 is a prime number
BaseRepresentation
bin11011110011110110000100…
…111000101001100111110101
3121001001201112010000200110201
4123303312010320221213311
5112012411401330200003
61112044235551120501
734522415100630223
oct3363660470514765
9531051463020421
10122310013131253
1135a76426884a82
12118745bbb13131
135332a28126c7c
14222bb9c841b13
15e2186dde5b1d
hex6f3d84e299f5

122310013131253 has 2 divisors, whose sum is σ = 122310013131254. Its totient is φ = 122310013131252.

The previous prime is 122310013131191. The next prime is 122310013131409. The reversal of 122310013131253 is 352131310013221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 91274674073284 + 31035339057969 = 9553778^2 + 5570937^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-122310013131253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122310013135253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61155006565626 + 61155006565627.

It is an arithmetic number, because the mean of its divisors is an integer number (61155006565627).

Almost surely, 2122310013131253 is an apocalyptic number.

It is an amenable number.

122310013131253 is a deficient number, since it is larger than the sum of its proper divisors (1).

122310013131253 is an equidigital number, since it uses as much as digits as its factorization.

122310013131253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3240, while the sum is 28.

Adding to 122310013131253 its reverse (352131310013221), we get a palindrome (474441323144474).

The spelling of 122310013131253 in words is "one hundred twenty-two trillion, three hundred ten billion, thirteen million, one hundred thirty-one thousand, two hundred fifty-three".