Base | Representation |
---|---|
bin | 11011110011110111010010… |
… | …110010101110111101111011 |
3 | 121001001211220012111211000021 |
4 | 123303313102302232331323 |
5 | 112012422040433000011 |
6 | 1112045013402151311 |
7 | 34522462351563343 |
oct | 3363672262567573 |
9 | 531054805454007 |
10 | 122311320203131 |
11 | 35a76a37672474 |
12 | 118749057b2537 |
13 | 5332ba5b69a97 |
14 | 222bc84283d23 |
15 | e218e8a31471 |
hex | 6f3dd2caef7b |
122311320203131 has 2 divisors, whose sum is σ = 122311320203132. Its totient is φ = 122311320203130.
The previous prime is 122311320203099. The next prime is 122311320203159. The reversal of 122311320203131 is 131302023113221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 122311320203131 - 25 = 122311320203099 is a prime.
It is a super-2 number, since 2×1223113202031312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 122311320203096 and 122311320203105.
It is not a weakly prime, because it can be changed into another prime (122311320203161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61155660101565 + 61155660101566.
It is an arithmetic number, because the mean of its divisors is an integer number (61155660101566).
Almost surely, 2122311320203131 is an apocalyptic number.
122311320203131 is a deficient number, since it is larger than the sum of its proper divisors (1).
122311320203131 is an equidigital number, since it uses as much as digits as its factorization.
122311320203131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 122311320203131 its reverse (131302023113221), we get a palindrome (253613343316352).
The spelling of 122311320203131 in words is "one hundred twenty-two trillion, three hundred eleven billion, three hundred twenty million, two hundred three thousand, one hundred thirty-one".
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