Base | Representation |
---|---|
bin | 10001110011001000010… |
… | …011000001011111110011 |
3 | 11022221010010000212202021 |
4 | 101303020103001133303 |
5 | 130014433033022011 |
6 | 2333522041132311 |
7 | 154240221111133 |
oct | 21631023013763 |
9 | 4287103025667 |
10 | 1223131142131 |
11 | 4317aa708588 |
12 | 17907418a097 |
13 | 8b4578a2462 |
14 | 432b25d2ac3 |
15 | 21c3a7a2471 |
hex | 11cc84c17f3 |
1223131142131 has 2 divisors, whose sum is σ = 1223131142132. Its totient is φ = 1223131142130.
The previous prime is 1223131142119. The next prime is 1223131142141. The reversal of 1223131142131 is 1312411313221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1223131142131 - 27 = 1223131142003 is a prime.
It is a super-2 number, since 2×12231311421312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1223131142096 and 1223131142105.
It is not a weakly prime, because it can be changed into another prime (1223131142141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611565571065 + 611565571066.
It is an arithmetic number, because the mean of its divisors is an integer number (611565571066).
Almost surely, 21223131142131 is an apocalyptic number.
1223131142131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1223131142131 is an equidigital number, since it uses as much as digits as its factorization.
1223131142131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 864, while the sum is 25.
Adding to 1223131142131 its reverse (1312411313221), we get a palindrome (2535542455352).
The spelling of 1223131142131 in words is "one trillion, two hundred twenty-three billion, one hundred thirty-one million, one hundred forty-two thousand, one hundred thirty-one".
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