Base | Representation |
---|---|
bin | 1011000111111110000101… |
… | …0000101100000010110011 |
3 | 1121022022202211101202202022 |
4 | 2301333201100230002303 |
5 | 3100400204042440034 |
6 | 42003032542342055 |
7 | 2401462145146331 |
oct | 261774120540263 |
9 | 47268684352668 |
10 | 12231551140019 |
11 | 399640a819532 |
12 | 145668188a92b |
13 | 6a9579560383 |
14 | 304020120b51 |
15 | 16328626ab2e |
hex | b1fe142c0b3 |
12231551140019 has 2 divisors, whose sum is σ = 12231551140020. Its totient is φ = 12231551140018.
The previous prime is 12231551140001. The next prime is 12231551140021. The reversal of 12231551140019 is 91004115513221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12231551140019 - 28 = 12231551139763 is a prime.
It is a super-2 number, since 2×122315511400192 (a number of 27 digits) contains 22 as substring.
Together with 12231551140021, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12231551140049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6115775570009 + 6115775570010.
It is an arithmetic number, because the mean of its divisors is an integer number (6115775570010).
Almost surely, 212231551140019 is an apocalyptic number.
12231551140019 is a deficient number, since it is larger than the sum of its proper divisors (1).
12231551140019 is an equidigital number, since it uses as much as digits as its factorization.
12231551140019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 35.
The spelling of 12231551140019 in words is "twelve trillion, two hundred thirty-one billion, five hundred fifty-one million, one hundred forty thousand, nineteen".
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