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12231551140019 is a prime number
BaseRepresentation
bin1011000111111110000101…
…0000101100000010110011
31121022022202211101202202022
42301333201100230002303
53100400204042440034
642003032542342055
72401462145146331
oct261774120540263
947268684352668
1012231551140019
11399640a819532
12145668188a92b
136a9579560383
14304020120b51
1516328626ab2e
hexb1fe142c0b3

12231551140019 has 2 divisors, whose sum is σ = 12231551140020. Its totient is φ = 12231551140018.

The previous prime is 12231551140001. The next prime is 12231551140021. The reversal of 12231551140019 is 91004115513221.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12231551140019 - 28 = 12231551139763 is a prime.

It is a super-2 number, since 2×122315511400192 (a number of 27 digits) contains 22 as substring.

Together with 12231551140021, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12231551140049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6115775570009 + 6115775570010.

It is an arithmetic number, because the mean of its divisors is an integer number (6115775570010).

Almost surely, 212231551140019 is an apocalyptic number.

12231551140019 is a deficient number, since it is larger than the sum of its proper divisors (1).

12231551140019 is an equidigital number, since it uses as much as digits as its factorization.

12231551140019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 35.

The spelling of 12231551140019 in words is "twelve trillion, two hundred thirty-one billion, five hundred fifty-one million, one hundred forty thousand, nineteen".