Base | Representation |
---|---|
bin | 10001110011001100011… |
… | …110010011111100010011 |
3 | 11022221021222212200222101 |
4 | 101303030132103330103 |
5 | 130020104002211011 |
6 | 2333533023021231 |
7 | 154242031510045 |
oct | 21631436237423 |
9 | 4287258780871 |
10 | 1223201210131 |
11 | 43183621571a |
12 | 17909373a817 |
13 | 8b469265c04 |
14 | 432bba31a95 |
15 | 21c419e32c1 |
hex | 11ccc793f13 |
1223201210131 has 2 divisors, whose sum is σ = 1223201210132. Its totient is φ = 1223201210130.
The previous prime is 1223201210129. The next prime is 1223201210167. The reversal of 1223201210131 is 1310121023221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1223201210131 - 21 = 1223201210129 is a prime.
It is a super-2 number, since 2×12232012101312 (a number of 25 digits) contains 22 as substring.
Together with 1223201210129, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1223201210099 and 1223201210108.
It is not a weakly prime, because it can be changed into another prime (1223201210111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611600605065 + 611600605066.
It is an arithmetic number, because the mean of its divisors is an integer number (611600605066).
Almost surely, 21223201210131 is an apocalyptic number.
1223201210131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1223201210131 is an equidigital number, since it uses as much as digits as its factorization.
1223201210131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1223201210131 its reverse (1310121023221), we get a palindrome (2533322233352).
The spelling of 1223201210131 in words is "one trillion, two hundred twenty-three billion, two hundred one million, two hundred ten thousand, one hundred thirty-one".
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