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122321032330207 is a prime number
BaseRepresentation
bin11011110100000000010101…
…101011100011101111011111
3121001002202222001120222201111
4123310000111223203233133
5112013101433234031312
61112053301222522451
734523255132364544
oct3364002553435737
9531082861528644
10122321032330207
1135a80070936277
1211876776296427
135333a93014239
14222c5260acbcb
15e21cb64c88a7
hex6f4015ae3bdf

122321032330207 has 2 divisors, whose sum is σ = 122321032330208. Its totient is φ = 122321032330206.

The previous prime is 122321032330187. The next prime is 122321032330213. The reversal of 122321032330207 is 702033230123221.

It is a strong prime.

It is an emirp because it is prime and its reverse (702033230123221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 122321032330207 - 243 = 113524939307999 is a prime.

It is a super-2 number, since 2×1223210323302072 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122321032330267) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61160516165103 + 61160516165104.

It is an arithmetic number, because the mean of its divisors is an integer number (61160516165104).

Almost surely, 2122321032330207 is an apocalyptic number.

122321032330207 is a deficient number, since it is larger than the sum of its proper divisors (1).

122321032330207 is an equidigital number, since it uses as much as digits as its factorization.

122321032330207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 31.

Adding to 122321032330207 its reverse (702033230123221), we get a palindrome (824354262453428).

The spelling of 122321032330207 in words is "one hundred twenty-two trillion, three hundred twenty-one billion, thirty-two million, three hundred thirty thousand, two hundred seven".