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122325043415551 is a prime number
BaseRepresentation
bin11011110100000100000100…
…110000101000100111111111
3121001010011022121011020101221
4123310010010300220213333
5112013133142103244201
61112055203230214211
734523456416141114
oct3364040460504777
9531104277136357
10122325043415551
1135a8183a001039
12118774b5654367
135334282017512
14222c7c6aaa90b
15e21e4d6dd4a1
hex6f4104c289ff

122325043415551 has 2 divisors, whose sum is σ = 122325043415552. Its totient is φ = 122325043415550.

The previous prime is 122325043415507. The next prime is 122325043415579. The reversal of 122325043415551 is 155514340523221.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 122325043415551 - 29 = 122325043415039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 122325043415498 and 122325043415507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122325043415851) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61162521707775 + 61162521707776.

It is an arithmetic number, because the mean of its divisors is an integer number (61162521707776).

Almost surely, 2122325043415551 is an apocalyptic number.

122325043415551 is a deficient number, since it is larger than the sum of its proper divisors (1).

122325043415551 is an equidigital number, since it uses as much as digits as its factorization.

122325043415551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720000, while the sum is 43.

Adding to 122325043415551 its reverse (155514340523221), we get a palindrome (277839383938772).

The spelling of 122325043415551 in words is "one hundred twenty-two trillion, three hundred twenty-five billion, forty-three million, four hundred fifteen thousand, five hundred fifty-one".