Base | Representation |
---|---|
bin | 11011110100000100001000… |
… | …111111000111010110111101 |
3 | 121001010011111112120120110101 |
4 | 123310010020333013112331 |
5 | 112013133313231222232 |
6 | 1112055214242041101 |
7 | 34523461236623416 |
oct | 3364041077072675 |
9 | 531104445516411 |
10 | 122325114320317 |
11 | 35a8187602a917 |
12 | 11877515349191 |
13 | 5334293911abc |
14 | 222c7d228680d |
15 | e21e54a471e7 |
hex | 6f4108fc75bd |
122325114320317 has 2 divisors, whose sum is σ = 122325114320318. Its totient is φ = 122325114320316.
The previous prime is 122325114320273. The next prime is 122325114320327. The reversal of 122325114320317 is 713023411523221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 73654482963961 + 48670631356356 = 8582219^2 + 6976434^2 .
It is a cyclic number.
It is not a de Polignac number, because 122325114320317 - 243 = 113529021298109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122325114320327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61162557160158 + 61162557160159.
It is an arithmetic number, because the mean of its divisors is an integer number (61162557160159).
Almost surely, 2122325114320317 is an apocalyptic number.
It is an amenable number.
122325114320317 is a deficient number, since it is larger than the sum of its proper divisors (1).
122325114320317 is an equidigital number, since it uses as much as digits as its factorization.
122325114320317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 37.
Adding to 122325114320317 its reverse (713023411523221), we get a palindrome (835348525843538).
The spelling of 122325114320317 in words is "one hundred twenty-two trillion, three hundred twenty-five billion, one hundred fourteen million, three hundred twenty thousand, three hundred seventeen".
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