Base | Representation |
---|---|
bin | 11011110100000100010101… |
… | …010000010000010011101101 |
3 | 121001010012000212212022000002 |
4 | 123310010111100100103231 |
5 | 112013134223423440023 |
6 | 1112055250513314045 |
7 | 34523466316230014 |
oct | 3364042520202355 |
9 | 531105025768002 |
10 | 122325320140013 |
11 | 35a81971228241 |
12 | 11877572265925 |
13 | 53342c7455cc3 |
14 | 222c811741a7b |
15 | e21e67b50b28 |
hex | 6f41154104ed |
122325320140013 has 2 divisors, whose sum is σ = 122325320140014. Its totient is φ = 122325320140012.
The previous prime is 122325320139959. The next prime is 122325320140043. The reversal of 122325320140013 is 310041023523221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 122102986200484 + 222333939529 = 11050022^2 + 471523^2 .
It is a cyclic number.
It is not a de Polignac number, because 122325320140013 - 26 = 122325320139949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122325320140043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61162660070006 + 61162660070007.
It is an arithmetic number, because the mean of its divisors is an integer number (61162660070007).
Almost surely, 2122325320140013 is an apocalyptic number.
It is an amenable number.
122325320140013 is a deficient number, since it is larger than the sum of its proper divisors (1).
122325320140013 is an equidigital number, since it uses as much as digits as its factorization.
122325320140013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 122325320140013 its reverse (310041023523221), we get a palindrome (432366343663234).
The spelling of 122325320140013 in words is "one hundred twenty-two trillion, three hundred twenty-five billion, three hundred twenty million, one hundred forty thousand, thirteen".
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