Base | Representation |
---|---|
bin | 11011110100001000101110… |
… | …101010001011100100100011 |
3 | 121001010122012220121210200112 |
4 | 123310020232222023210203 |
5 | 112013223411040142201 |
6 | 1112101351205041535 |
7 | 34524024314556065 |
oct | 3364105652134443 |
9 | 531118186553615 |
10 | 122330041334051 |
11 | 35a839742171a1 |
12 | 1187846b3b62ab |
13 | 533489a5c7845 |
14 | 222cb3c789735 |
15 | e221423830bb |
hex | 6f422ea8b923 |
122330041334051 has 2 divisors, whose sum is σ = 122330041334052. Its totient is φ = 122330041334050.
The previous prime is 122330041334029. The next prime is 122330041334099. The reversal of 122330041334051 is 150433140033221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 122330041334051 - 214 = 122330041317667 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 122330041333999 and 122330041334017.
It is not a weakly prime, because it can be changed into another prime (122330041333051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61165020667025 + 61165020667026.
It is an arithmetic number, because the mean of its divisors is an integer number (61165020667026).
Almost surely, 2122330041334051 is an apocalyptic number.
122330041334051 is a deficient number, since it is larger than the sum of its proper divisors (1).
122330041334051 is an equidigital number, since it uses as much as digits as its factorization.
122330041334051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 122330041334051 its reverse (150433140033221), we get a palindrome (272763181367272).
The spelling of 122330041334051 in words is "one hundred twenty-two trillion, three hundred thirty billion, forty-one million, three hundred thirty-four thousand, fifty-one".
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