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122330047894147 is a prime number
BaseRepresentation
bin11011110100001000101111…
…000011001101001010000011
3121001010122020100222002110001
4123310020233003031022003
5112013223414230103042
61112101352001420431
734524024424410532
oct3364105703151203
9531118210862401
10122330047894147
1135a83977997965
121187847163a717
13533489ba83762
14222cb3d5b6319
15e22142c2bbb7
hex6f422f0cd283

122330047894147 has 2 divisors, whose sum is σ = 122330047894148. Its totient is φ = 122330047894146.

The previous prime is 122330047894141. The next prime is 122330047894169. The reversal of 122330047894147 is 741498740033221.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (741498740033221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 122330047894147 - 239 = 121780292080259 is a prime.

It is not a weakly prime, because it can be changed into another prime (122330047894141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61165023947073 + 61165023947074.

It is an arithmetic number, because the mean of its divisors is an integer number (61165023947074).

Almost surely, 2122330047894147 is an apocalyptic number.

122330047894147 is a deficient number, since it is larger than the sum of its proper divisors (1).

122330047894147 is an equidigital number, since it uses as much as digits as its factorization.

122330047894147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8128512, while the sum is 55.

The spelling of 122330047894147 in words is "one hundred twenty-two trillion, three hundred thirty billion, forty-seven million, eight hundred ninety-four thousand, one hundred forty-seven".