Base | Representation |
---|---|
bin | 1011001000000011111110… |
… | …0000010101101110101011 |
3 | 1121022110212000122002011112 |
4 | 2302000333200111232223 |
5 | 3100411423332114402 |
6 | 42003453504220535 |
7 | 2401546264614635 |
oct | 262007740255653 |
9 | 47273760562145 |
10 | 12233132301227 |
11 | 39970512a3332 |
12 | 1456a4330a74b |
13 | 6a976bccb416 |
14 | 30413010da55 |
15 | 163329e97e52 |
hex | b203f815bab |
12233132301227 has 2 divisors, whose sum is σ = 12233132301228. Its totient is φ = 12233132301226.
The previous prime is 12233132301211. The next prime is 12233132301277. The reversal of 12233132301227 is 72210323133221.
12233132301227 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12233132301227 - 24 = 12233132301211 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12233132301193 and 12233132301202.
It is not a weakly prime, because it can be changed into another prime (12233132301277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6116566150613 + 6116566150614.
It is an arithmetic number, because the mean of its divisors is an integer number (6116566150614).
Almost surely, 212233132301227 is an apocalyptic number.
12233132301227 is a deficient number, since it is larger than the sum of its proper divisors (1).
12233132301227 is an equidigital number, since it uses as much as digits as its factorization.
12233132301227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 32.
Adding to 12233132301227 its reverse (72210323133221), we get a palindrome (84443455434448).
The spelling of 12233132301227 in words is "twelve trillion, two hundred thirty-three billion, one hundred thirty-two million, three hundred one thousand, two hundred twenty-seven".
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