Base | Representation |
---|---|
bin | 111000111110000011… |
… | …1001011100011100101 |
3 | 102200210011211002010002 |
4 | 1301330013023203211 |
5 | 4001023340411123 |
6 | 132111451311045 |
7 | 11560506146444 |
oct | 1617407134345 |
9 | 380704732102 |
10 | 122341341413 |
11 | 47980552625 |
12 | 1b863a4b485 |
13 | b6c92a57a5 |
14 | 5cc8296d5b |
15 | 32b07e1528 |
hex | 1c7c1cb8e5 |
122341341413 has 2 divisors, whose sum is σ = 122341341414. Its totient is φ = 122341341412.
The previous prime is 122341341403. The next prime is 122341341439. The reversal of 122341341413 is 314143143221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 116210764609 + 6130576804 = 340897^2 + 78298^2 .
It is an emirp because it is prime and its reverse (314143143221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122341341413 - 210 = 122341340389 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122341341403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61170670706 + 61170670707.
It is an arithmetic number, because the mean of its divisors is an integer number (61170670707).
Almost surely, 2122341341413 is an apocalyptic number.
It is an amenable number.
122341341413 is a deficient number, since it is larger than the sum of its proper divisors (1).
122341341413 is an equidigital number, since it uses as much as digits as its factorization.
122341341413 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6912, while the sum is 29.
Adding to 122341341413 its reverse (314143143221), we get a palindrome (436484484634).
The spelling of 122341341413 in words is "one hundred twenty-two billion, three hundred forty-one million, three hundred forty-one thousand, four hundred thirteen".
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