Base | Representation |
---|---|
bin | 11011110100010101000101… |
… | …110010100111101110110001 |
3 | 121001011220110221002120111201 |
4 | 123310111011302213232301 |
5 | 112013433101431340101 |
6 | 1112111424231211201 |
7 | 34525004244251002 |
oct | 3364250562475661 |
9 | 531156427076451 |
10 | 122343314324401 |
11 | 35a895654a8305 |
12 | 1187ab54516b01 |
13 | 5335c043cb4a1 |
14 | 222d63b4971a9 |
15 | e2266c75ae01 |
hex | 6f4545ca7bb1 |
122343314324401 has 2 divisors, whose sum is σ = 122343314324402. Its totient is φ = 122343314324400.
The previous prime is 122343314324281. The next prime is 122343314324437. The reversal of 122343314324401 is 104423413343221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 77521949669025 + 44821364655376 = 8804655^2 + 6694876^2 .
It is a cyclic number.
It is not a de Polignac number, because 122343314324401 - 215 = 122343314291633 is a prime.
It is not a weakly prime, because it can be changed into another prime (122343314324471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61171657162200 + 61171657162201.
It is an arithmetic number, because the mean of its divisors is an integer number (61171657162201).
Almost surely, 2122343314324401 is an apocalyptic number.
It is an amenable number.
122343314324401 is a deficient number, since it is larger than the sum of its proper divisors (1).
122343314324401 is an equidigital number, since it uses as much as digits as its factorization.
122343314324401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 37.
Adding to 122343314324401 its reverse (104423413343221), we get a palindrome (226766727667622).
The spelling of 122343314324401 in words is "one hundred twenty-two trillion, three hundred forty-three billion, three hundred fourteen million, three hundred twenty-four thousand, four hundred one".
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