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122343314324437 is a prime number
BaseRepresentation
bin11011110100010101000101…
…110010100111101111010101
3121001011220110221002120120001
4123310111011302213233111
5112013433101431340222
61112111424231211301
734525004244251053
oct3364250562475725
9531156427076501
10122343314324437
1135a895654a8338
121187ab54516b31
135335c043cb4cb
14222d63b4971d3
15e2266c75ae27
hex6f4545ca7bd5

122343314324437 has 2 divisors, whose sum is σ = 122343314324438. Its totient is φ = 122343314324436.

The previous prime is 122343314324401. The next prime is 122343314324447. The reversal of 122343314324437 is 734423413343221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108040100446756 + 14303213877681 = 10394234^2 + 3781959^2 .

It is a cyclic number.

It is not a de Polignac number, because 122343314324437 - 227 = 122343180106709 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122343314324447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61171657162218 + 61171657162219.

It is an arithmetic number, because the mean of its divisors is an integer number (61171657162219).

Almost surely, 2122343314324437 is an apocalyptic number.

It is an amenable number.

122343314324437 is a deficient number, since it is larger than the sum of its proper divisors (1).

122343314324437 is an equidigital number, since it uses as much as digits as its factorization.

122343314324437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3483648, while the sum is 46.

Adding to 122343314324437 its reverse (734423413343221), we get a palindrome (856766727667658).

The spelling of 122343314324437 in words is "one hundred twenty-two trillion, three hundred forty-three billion, three hundred fourteen million, three hundred twenty-four thousand, four hundred thirty-seven".