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122344155149893 is a prime number
BaseRepresentation
bin11011110100010101110111…
…111010000111011001000101
3121001011222122112020221020121
4123310111313322013121011
5112013441312204244033
61112112043505101541
734525034134201165
oct3364256772073105
9531158575227217
10122344155149893
1135a89957092a06
121187b14a0278b1
135336009676871
14222d6bb00c5a5
15e226bb49962d
hex6f4577e87645

122344155149893 has 2 divisors, whose sum is σ = 122344155149894. Its totient is φ = 122344155149892.

The previous prime is 122344155149873. The next prime is 122344155149917. The reversal of 122344155149893 is 398941551443221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 115191643511169 + 7152511638724 = 10732737^2 + 2674418^2 .

It is a cyclic number.

It is not a de Polignac number, because 122344155149893 - 213 = 122344155141701 is a prime.

It is a super-2 number, since 2×1223441551498932 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122344155149873) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61172077574946 + 61172077574947.

It is an arithmetic number, because the mean of its divisors is an integer number (61172077574947).

Almost surely, 2122344155149893 is an apocalyptic number.

It is an amenable number.

122344155149893 is a deficient number, since it is larger than the sum of its proper divisors (1).

122344155149893 is an equidigital number, since it uses as much as digits as its factorization.

122344155149893 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 37324800, while the sum is 61.

The spelling of 122344155149893 in words is "one hundred twenty-two trillion, three hundred forty-four billion, one hundred fifty-five million, one hundred forty-nine thousand, eight hundred ninety-three".