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122344405110253 is a prime number
BaseRepresentation
bin11011110100010110000110…
…110011101000110111101101
3121001012000021221121020101201
4123310112012303220313231
5112013442320202012003
61112112124354405501
734525043260626454
oct3364260663506755
9531160257536351
10122344405110253
1135a89a75199917
121187b1b9890891
1353360493a41c1
14222d7022b7b9b
15e226d33c1b1d
hex6f4586ce8ded

122344405110253 has 2 divisors, whose sum is σ = 122344405110254. Its totient is φ = 122344405110252.

The previous prime is 122344405110241. The next prime is 122344405110329. The reversal of 122344405110253 is 352011504443221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75777947732809 + 46566457377444 = 8705053^2 + 6823962^2 .

It is a cyclic number.

It is not a de Polignac number, because 122344405110253 - 221 = 122344403013101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122344405110233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61172202555126 + 61172202555127.

It is an arithmetic number, because the mean of its divisors is an integer number (61172202555127).

Almost surely, 2122344405110253 is an apocalyptic number.

It is an amenable number.

122344405110253 is a deficient number, since it is larger than the sum of its proper divisors (1).

122344405110253 is an equidigital number, since it uses as much as digits as its factorization.

122344405110253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 115200, while the sum is 37.

Adding to 122344405110253 its reverse (352011504443221), we get a palindrome (474355909553474).

The spelling of 122344405110253 in words is "one hundred twenty-two trillion, three hundred forty-four billion, four hundred five million, one hundred ten thousand, two hundred fifty-three".