Base | Representation |
---|---|
bin | 11011110100010110101101… |
… | …010011100110111010010111 |
3 | 121001012001221222000002220212 |
4 | 123310112231103212322113 |
5 | 112014000131030300142 |
6 | 1112112312430520035 |
7 | 34525065263050124 |
oct | 3364265523467227 |
9 | 531161858002825 |
10 | 122345051025047 |
11 | 35a8a2768581a4 |
12 | 1187b35a06601b |
13 | 53361201578c6 |
14 | 222d763db374b |
15 | e2271ee5dd82 |
hex | 6f45ad4e6e97 |
122345051025047 has 2 divisors, whose sum is σ = 122345051025048. Its totient is φ = 122345051025046.
The previous prime is 122345051025031. The next prime is 122345051025139. The reversal of 122345051025047 is 740520150543221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 122345051025047 - 24 = 122345051025031 is a prime.
It is a super-3 number, since 3×1223450510250473 (a number of 43 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 122345051024995 and 122345051025013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122345051025247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61172525512523 + 61172525512524.
It is an arithmetic number, because the mean of its divisors is an integer number (61172525512524).
Almost surely, 2122345051025047 is an apocalyptic number.
122345051025047 is a deficient number, since it is larger than the sum of its proper divisors (1).
122345051025047 is an equidigital number, since it uses as much as digits as its factorization.
122345051025047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 336000, while the sum is 41.
The spelling of 122345051025047 in words is "one hundred twenty-two trillion, three hundred forty-five billion, fifty-one million, twenty-five thousand, forty-seven".
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