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12240737961407 = 13193440747797
BaseRepresentation
bin1011001000100000010011…
…0101101000010110111111
31121100012111002000122112022
42302020010311220112333
53101023012404231112
642011152320030355
72402235616636214
oct262100465502677
947305432018468
1012240737961407
11399a2a45113aa
1214584064623bb
136aa3b1932367
14304652287b0b
15163622a4bd72
hexb2204d685bf

12240737961407 has 4 divisors (see below), whose sum is σ = 12334178709336. Its totient is φ = 12147297213480.

The previous prime is 12240737961341. The next prime is 12240737961437. The reversal of 12240737961407 is 70416973704221.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12240737961407 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12240737961437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46720373768 + ... + 46720374029.

It is an arithmetic number, because the mean of its divisors is an integer number (3083544677334).

Almost surely, 212240737961407 is an apocalyptic number.

12240737961407 is a deficient number, since it is larger than the sum of its proper divisors (93440747929).

12240737961407 is an equidigital number, since it uses as much as digits as its factorization.

12240737961407 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93440747928.

The product of its (nonzero) digits is 3556224, while the sum is 53.

The spelling of 12240737961407 in words is "twelve trillion, two hundred forty billion, seven hundred thirty-seven million, nine hundred sixty-one thousand, four hundred seven".

Divisors: 1 131 93440747797 12240737961407