Base | Representation |
---|---|
bin | 10110110011010010… |
… | …10001100101111111 |
3 | 1011121010101002012112 |
4 | 23121221101211333 |
5 | 200032300113211 |
6 | 5342411524235 |
7 | 612232162145 |
oct | 133151214577 |
9 | 34533332175 |
10 | 12241410431 |
11 | 5211a58928 |
12 | 245775967b |
13 | 120118a633 |
14 | 841add595 |
15 | 4b9a5988b |
hex | 2d9a5197f |
12241410431 has 2 divisors, whose sum is σ = 12241410432. Its totient is φ = 12241410430.
The previous prime is 12241410413. The next prime is 12241410437. The reversal of 12241410431 is 13401414221.
Together with previous prime (12241410413) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12241410431 - 26 = 12241410367 is a prime.
It is a super-2 number, since 2×122414104312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12241410397 and 12241410406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12241410437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6120705215 + 6120705216.
It is an arithmetic number, because the mean of its divisors is an integer number (6120705216).
Almost surely, 212241410431 is an apocalyptic number.
12241410431 is a deficient number, since it is larger than the sum of its proper divisors (1).
12241410431 is an equidigital number, since it uses as much as digits as its factorization.
12241410431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 12241410431 its reverse (13401414221), we get a palindrome (25642824652).
The spelling of 12241410431 in words is "twelve billion, two hundred forty-one million, four hundred ten thousand, four hundred thirty-one".
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